Question 1.13  [ENDORSED]

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Matthew 1C
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Question 1.13

Postby Matthew 1C » Sat Oct 14, 2017 6:23 pm

a) Use the Rydberg formula for atomic hydrogen to calculate the wavelength of radiation generated by the transition from n=4 to n=2. I understand the calculation of the change in energy, but in calculating the wavelength using the equation lambda= ch/E, why do we discard the negative?

Chem_Mod
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Re: Question 1.13  [ENDORSED]

Postby Chem_Mod » Sat Oct 14, 2017 8:15 pm

The negative has to do with if the light is being absorbed or emitted. If it is absorbed, it is positive. Emitted, it is negative. Because this transition is a lowering in energy, this energy is emitted as a photon.


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