Chapter 1 #57  [ENDORSED]

H-Atom ()

Moderators: Chem_Mod, Chem_Admin

Posts: 58
Joined: Thu Jul 13, 2017 3:00 am
Been upvoted: 1 time

Chapter 1 #57

Postby sofiakavanaugh » Sun Oct 29, 2017 10:53 pm

Lines in the Balmer series of the hydrogen spectrum are observed at 656.3, 486.1, 434.0, and 410.2 nm. What is the wavelength of the next line in the series?

Could someone please explain to me how they used the values given in the problem to determine which values to plug in the Rydberg Equation?


Posts: 19
Joined: Fri Sep 29, 2017 7:07 am

Re: Chapter 1 #57  [ENDORSED]

Postby sandros » Mon Oct 30, 2017 1:38 am

You know that for the Balmer series, n1=2 and you have the wavelength of the last spectral line so if you plug in all your variables into Rydberg's formula you'll be able to get the n2 for the last line. The next line in the series corresponds to a transition from n1=2 to n2= whatever you got from your rydberg's equation +1.
Therefore you can calculate the Energy and then the wavelength by respectively using rydberg's equation again and the E= h x C/lambda .

Hope this helps.

Posts: 20
Joined: Fri Sep 29, 2017 7:07 am

Re: Chapter 1 #57

Postby clairedisc3b » Tue Oct 31, 2017 6:37 pm

Just to clarify though - in the solutions manual they say that n2 = 7. The values given are 656.3, 486.1, 434.0, and 410.2 nm. Does that mean that 656.3 is 3, 486.1 is 4, 434 is 5, 410.2 is 6? ie that the lines don't start at the second but at the third energy level?

Return to “Bohr Frequency Condition, H-Atom , Atomic Spectroscopy”

Who is online

Users browsing this forum: No registered users and 1 guest