Rydberg  [ENDORSED]

H-Atom ()

Moderators: Chem_Mod, Chem_Admin

Kuldeep Gill 1H
Posts: 44
Joined: Fri Apr 06, 2018 11:02 am
Been upvoted: 1 time


Postby Kuldeep Gill 1H » Tue Apr 24, 2018 5:53 pm

Hi I was a little confused when doing the Rydberg equation and finding the energy difference between the two levels I got a negative number which I know means that energy is being emitted to go to a lower energy level so I was wondering if when we state the energy difference would we state it as a positive number or a negative number? And to follow that up when finding from that energy level the frequency or wavelength of that energy would we make it positive or negative? Thanks!

Posts: 31
Joined: Fri Apr 06, 2018 11:02 am

Re: Rydberg

Postby kendallbottrell » Tue Apr 24, 2018 11:02 pm

Just the energy difference by itself can be stated as a negative number because, like you said, it just shows that light was being emitted. However, if you want to find the wavelength, you need to omit the negative signs because there is no such thing as a negative wavelength - same thing goes for frequencies.

Madison Hacker 1L
Posts: 30
Joined: Fri Apr 06, 2018 11:03 am

Re: Rydberg

Postby Madison Hacker 1L » Sun Apr 29, 2018 5:19 pm

I also had trouble with this in the beginning. If you think conceptually though, there can't be a negative frequency or wavelength, so I would remove it if it doesn't make sense to the concept.

Posts: 19582
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 888 times

Re: Rydberg  [ENDORSED]

Postby Chem_Mod » Sun Apr 29, 2018 5:45 pm

So the negative number arises because you are thinking about photons in the Rydberg formula while the energy difference you find is that for the electron in the H-atom. Since electron lost its energy, by conservation of energy, the amount of energy loss is converted into photons.

Yitzchak Jacobson 1F
Posts: 31
Joined: Wed Nov 22, 2017 3:00 am

Re: Rydberg

Postby Yitzchak Jacobson 1F » Mon Apr 30, 2018 4:47 pm

Ive had a similar problem regarding this equation also, and I realized that removing the negative sign in general allows more a more proficient answer. Hope this helps you :)

Return to “Bohr Frequency Condition, H-Atom , Atomic Spectroscopy”

Who is online

Users browsing this forum: No registered users and 1 guest