H-Atom ()

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Ramsha Dis1B
Posts: 32
Joined: Fri Sep 28, 2018 12:19 am


Postby Ramsha Dis1B » Thu Oct 11, 2018 11:04 am

What does it mean when they say that the energies on the right of an expression have to be proportional to hR/n2, to have accounted for Rydberg’s formula?

Alyssa Wilson 2A
Posts: 65
Joined: Fri Sep 28, 2018 12:18 am

Re: H-Atom

Postby Alyssa Wilson 2A » Thu Oct 11, 2018 8:02 pm

I believe it states that the wavelength and frequency are inversely proportional; as one increases, the other decreases. So both sides of the expression have to be equal energies to cancel one another out, so that you are left with Rydberg's formula in the end.

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