## E(n)=-hR/n^2

H-Atom ($E_{n}=-\frac{hR}{n^{2}}$)

905085650
Posts: 62
Joined: Fri Sep 28, 2018 12:19 am

### E(n)=-hR/n^2

In the equation E(n)=-hR/n^2, where does the negative come from?

Thank you!

Diviya Khullar 1G
Posts: 59
Joined: Fri Sep 28, 2018 12:19 am

### Re: E(n)=-hR/n^2

The negative sign is there because a bound electron has lower energy than a free electron. So, it is there to represent the negative change in energy.

Ibrahim Malik 1H
Posts: 65
Joined: Fri Sep 28, 2018 12:27 am
Been upvoted: 1 time

### Re: E(n)=-hR/n^2

As electrons fall from orbitals (for example, n=2 to n=2), the electrons lose energy, hence the negative sign within Bohr's Equation. The negative sign basically signifies energy being lost in the system.

CaminaB_1D
Posts: 63
Joined: Fri Sep 28, 2018 12:16 am

### Re: E(n)=-hR/n^2

What does the 'h' represent here in this equation?

Sorry, disregard this question. I knew it was Planck's constant, just had it rounded in my notes