7th edition HW Problem 1.A15

[Lopez_Melissa-Dis4E]

Hello, can someone please explain how to solve HW Problem 1A.15 in the 7th edition of the textbook?

[Elena Maneffa 1E]

For a line at 102.6nm, we know that n1=1.

Then use the equation c=(wavelength)(frequency), but rearrange it to look like:

v= c/(wavelength)

So:

v=(2.998x10^8)/(102.6x10^-9) =2.922x10^15 s^-1.

We then need to find n2.


Use this equation: v=R((1/n1^2) - (1/n2^2).

Then you will get this if you rearrange:

1/n2^2 =(1/1^2) -(v/R)


Then plug in your givens.


(1/n2^2)=1-((2.922x10^15)/(3.29x10^15))

This is equal to o.112.

So...
(1/n2^2) =0.112.

n2^2=9

Take the square root on each side to solve for n2

n2=3.

n1=1 and n2=3.

[Elena Maneffa 1E]

Wait, actually, sorry. My TA said we can't use the equation from the book. We are supposed to use another one, so the above explanation is wrong. Sorry.