CHEMISTRY COMMUNITY

Is E = -hR/n^2 the Rydberg equation? My TA said that we shouldn't use the Rydberg equation in our calculations, but I've been using this one and I know it has the Rydberg constant in it.

The Rydberg Equation is R[1/n1^2-1/n2^2]= 1/lambda. We are encouraged to use En= -hR/n^2 and then Delta E= E(final)-E(initial).