Deriving Rydberg's Equation

H-Atom ()

Moderators: Chem_Mod, Chem_Admin

Timothy_Yueh_4L
Posts: 57
Joined: Fri Sep 28, 2018 12:28 am

Deriving Rydberg's Equation

Postby Timothy_Yueh_4L » Sun Oct 21, 2018 6:56 pm

How do you derive E = Rh (1/nf^2 – 1/ni^2) from v = R (1/nf^2 – 1/ni^2)?

WilliamNguyen_4L
Posts: 65
Joined: Fri Sep 28, 2018 12:28 am

Re: Deriving Rydberg's Equation

Postby WilliamNguyen_4L » Sun Oct 21, 2018 6:57 pm

Sinve E=hv we can rearrange it into E/h=v. Then we substitute E/h for v in rydberg’s equation and multiply by h on both sides to isolate E.

Grace Diaz 3F
Posts: 30
Joined: Fri Sep 28, 2018 12:24 am

Re: Deriving Rydberg's Equation

Postby Grace Diaz 3F » Sun Oct 21, 2018 11:16 pm

To calculate the differences between two energy levels you take the difference in their frequencies and end up with v=R[1/nf^2-1/ni^2]. Frequency=change in E/ h, is given by the Bohr frequency condition. If we substitute v for E/h, we can multiply the other side of the equation by plank's constant to get E=Rh[1/nf^2-1/ni^2].


Return to “Bohr Frequency Condition, H-Atom , Atomic Spectroscopy”

Who is online

Users browsing this forum: No registered users and 1 guest