## Deriving Rydberg's Equation

H-Atom ($E_{n}=-\frac{hR}{n^{2}}$)

Timothy_Yueh_4L
Posts: 57
Joined: Fri Sep 28, 2018 12:28 am

### Deriving Rydberg's Equation

How do you derive E = Rh (1/nf^2 – 1/ni^2) from v = R (1/nf^2 – 1/ni^2)?

WilliamNguyen_4L
Posts: 65
Joined: Fri Sep 28, 2018 12:28 am

### Re: Deriving Rydberg's Equation

Sinve E=hv we can rearrange it into E/h=v. Then we substitute E/h for v in rydberg’s equation and multiply by h on both sides to isolate E.

Grace Diaz 3F
Posts: 30
Joined: Fri Sep 28, 2018 12:24 am

### Re: Deriving Rydberg's Equation

To calculate the differences between two energy levels you take the difference in their frequencies and end up with v=R[1/nf^2-1/ni^2]. Frequency=change in E/ h, is given by the Bohr frequency condition. If we substitute v for E/h, we can multiply the other side of the equation by plank's constant to get E=Rh[1/nf^2-1/ni^2].