Page 1 of 1
Deriving Rydberg's Equation
Posted: Sun Oct 21, 2018 6:56 pm
by Timothy_Yueh_4L
How do you derive E = Rh (1/nf^2 – 1/ni^2) from v = R (1/nf^2 – 1/ni^2)?
Re: Deriving Rydberg's Equation
Posted: Sun Oct 21, 2018 6:57 pm
by WilliamNguyen_4L
Sinve E=hv we can rearrange it into E/h=v. Then we substitute E/h for v in rydberg’s equation and multiply by h on both sides to isolate E.
Re: Deriving Rydberg's Equation
Posted: Sun Oct 21, 2018 11:16 pm
by Grace Diaz 3F
To calculate the differences between two energy levels you take the difference in their frequencies and end up with v=R[1/nf^2-1/ni^2]. Frequency=change in E/ h, is given by the Bohr frequency condition. If we substitute v for E/h, we can multiply the other side of the equation by plank's constant to get E=Rh[1/nf^2-1/ni^2].