Rydberg Equation

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charlotte_jacobs_4I
Posts: 63
Joined: Fri Sep 28, 2018 12:29 am

Rydberg Equation

Postby charlotte_jacobs_4I » Tue Oct 23, 2018 10:09 pm

I have been looking around and I can't find a clear answer to tell me if in the Rydberg equation it is R((1/(the original value of n))-(1/(the final value of n)) or the opposite way for the final and initial values. Please let me know if you can! Thank you!

Yvonne Du
Posts: 64
Joined: Fri Sep 28, 2018 12:23 am

Re: Rydberg Equation

Postby Yvonne Du » Tue Oct 23, 2018 10:21 pm

I think in the book they stated that it should be n(initial)-n(final). I ran into the same problem. For one of the homework questions, I got a negative answer when I put n(initial)-n(final), but the answer key says it is positive. They flipped the other to get a positive number. I think I'll go with the initial-final as long as I don't get a negative number? Don't know if this helps.

charlotte_jacobs_4I
Posts: 63
Joined: Fri Sep 28, 2018 12:29 am

Re: Rydberg Equation

Postby charlotte_jacobs_4I » Tue Oct 23, 2018 10:25 pm

I was running into the same problem. I'm not sure but is the answer ever supposed to be negative?

Chloe Thorpe 1J
Posts: 77
Joined: Fri Sep 28, 2018 12:16 am

Re: Rydberg Equation

Postby Chloe Thorpe 1J » Tue Oct 23, 2018 10:35 pm

I was wondering this as well. The textbook says it's initial-final, so I've been using that for my calculations.

Hailey Boehm 2H
Posts: 71
Joined: Fri Sep 28, 2018 12:24 am

Re: Rydberg Equation

Postby Hailey Boehm 2H » Tue Oct 23, 2018 10:51 pm

I was also wondering about this. In the atomic spectra video module it says that the equation is v=-R[(1/n1^2) - (1/n2^2)], where n2>n1. This would mean n2 is n initial. However, Mr. Lavelle also recommends to not use this equation because it is really easy to mess up the signs, so you should just use En= -hr/n^2 and just subtract Efinal - E initial.

Ashita Tanwar 3H
Posts: 30
Joined: Fri Sep 28, 2018 12:23 am

Re: Rydberg Equation

Postby Ashita Tanwar 3H » Wed Oct 24, 2018 4:26 pm

Does this mean that the equation given in the atomic spectra module always uses the lower energy level "n" as n1, regardless of whether it is the final or initial value? For example, if an electron was dropping from n=4 to n=2, then would the equation be the same if the electron was jumping up from n=2 to n=4?

Tony Chung 2I
Posts: 60
Joined: Fri Sep 28, 2018 12:19 am

Re: Rydberg Equation

Postby Tony Chung 2I » Fri Oct 26, 2018 2:06 am

I believe I heard during lecture that it is final - initial.

Megan_Ervin_1F
Posts: 78
Joined: Fri Sep 28, 2018 12:18 am

Re: Rydberg Equation

Postby Megan_Ervin_1F » Sat Oct 27, 2018 5:15 pm

Does the order of final and initial change if the problem is having to do absorption instead of emission?


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