E=-hR/n^2 v. Rydberg forumla

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Seohyun Park 1L
Posts: 73
Joined: Fri Sep 28, 2018 12:29 am

E=-hR/n^2 v. Rydberg forumla

Postby Seohyun Park 1L » Wed Oct 24, 2018 9:08 pm

For 6th edition, 1.15, the problem asks to find the principal quantum number of a certain wavelength. Using Rydberg formula, I was able to find the right value of n2 assuming n1=1, but when I tried using E=-hR/n^2 and subtracting the energy level for n1 from n2, I failed to get the right n2 value. Is there a reason why? Shouldn't both methods technically work?

marisaimbroane1J
Posts: 69
Joined: Fri Sep 28, 2018 12:23 am

Re: E=-hR/n^2 v. Rydberg forumla

Postby marisaimbroane1J » Wed Oct 24, 2018 9:47 pm

Make sure you set the final and initial calculations equal to a negative energy. The E is emitted and therefore negative. I'm not sure if that will give you the right answer, but try starting with that and see if it works.


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