Rydberg equation
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Rydberg equation
In the video modules, professor Lavelle said that the Rydberg equation is v=-R [(1/n^2) - (1/n^2) , but the textbook says that the correct equation is v= R [(1/n^2) - (1/n^2). Why did professor Lavelle say to add a negative to the Rydberg constant and which one is correct?
Last edited by 305115396 on Sat Nov 03, 2018 11:40 pm, edited 1 time in total.
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Re: Rydberg equation
They are both correct. However, professor Lavelle prefers using negative signs to clearly indicate that higher n results in higher energy.
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Re: Rydberg equation
wait, how does a negative indicate a higher state? is it because electrons are negative and as you have more it becomes more negative?
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- Posts: 62
- Joined: Fri Sep 28, 2018 12:26 am
Re: Rydberg equation
Given that the energy is found through -(hR/n^2), increasing n would indicate greater energy as the result becomes less negative. If we use hR/n^2 to find the energy instead, increasing n would result in lower energy values, which is not correct.
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