Atomic Spectra Video Module

[Sarah Blake-2I]

How would I go about solving for the wavelength for this problem? Is it just c= wavelength x frequency and then solve for wavelength that way? Also, how do we know what region of the EM spectrum the wavelength is in?

28. The meter was defined in 1963 as 1,650,763.73 wavelengths of radiation emitted by krypton-86 (it has since been redefined). What is the wavelength of this krypton-86 radiation? To what region of the electromagnetic spectrum does this wavelength correspond (i.e. infrared, ultraviolet, x-ray, etc.)? What energy does one photon of this radiation have?

[805422680]

In 1m there are 1650763.73 wavelengths of krypton-86. There by dividing 1m by 1650762.72 wavelengths, the wavelength of each wave can be calculated to be 605.8nm. Thus, this falls under the visible spectrum. The energy can then be calculated by using the equation , followed by the equation E=hv.