## Finding Final n

H-Atom ($E_{n}=-\frac{hR}{n^{2}}$)

Ananta3G
Posts: 62
Joined: Wed Sep 18, 2019 12:19 am

### Finding Final n

Hi! I am having a bit of trouble doing 1A.15 in the textbook. I know I need to use -hR/n^2, find the change in E, and that n initial is equal to 2 because the wavelength, 102.6 nm is in the ultraviolet spectrum. I am unsure of how to put it all together. Here is the question: In the ultraviolet spectrum of atomic hydrogen, a line is observed at 102.6 nm. Determine the values of n for the initial and final energy levels of the electron during the emission of energy that leads to this spectral line.

Thank you!

Kevin Antony 2B
Posts: 65
Joined: Sat Sep 07, 2019 12:16 am

### Re: Finding Final n

102.6 nm would be part of the Lyman series which means n would equal 1.

haileyramsey-1c
Posts: 89
Joined: Thu Jul 25, 2019 12:18 am

### Re: Finding Final n

For this problem, you know the nfinal is 1 because UV light is the Lyman series. But you need to first use v=c/λ to find the frequency. Then you use Rydberg equation to find n2 which is 3.