## Atomic Spectra Post Mod Q

H-Atom ($E_{n}=-\frac{hR}{n^{2}}$)

Rose_Malki_3G
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### Atomic Spectra Post Mod Q

The meter was defined in 1963 as 1,650,763.73 wavelengths of radiation emitted by krypton-86 (it has since been redefined). What is the wavelength of this krypton-86 radiation?

How would you solve this problem?

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### Re: Atomic Spectra Post Mod Q

Since you are told that 1 meter is 1,650,763.73 wavelengths of radiation emitted by krypton-86, it is basically a 1 meter to 1,650,763.73 wavelengths ratio. To find 1 wavelength, just divide 1 meter by 1,650,763.73.

If you set it up as 1m=1,650,763.73 wavelengths, then your goal is to find 1 wavelength, so divide both sides by 1,650,763.73 to get your answer.