Sapling #11

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Kaili Valenzuela 2B
Posts: 82
Joined: Wed Sep 30, 2020 9:55 pm

Sapling #11

Postby Kaili Valenzuela 2B » Fri Oct 23, 2020 3:53 pm

Hello! I'm having difficultly figuring out how to solve this question on sapling if someone could please help!

A blue line is observed at 486.1 nm in the spectrum of atomic hydrogen. Determine the values of n for the beginning and ending energy levels of the electron during the emission of energy that leads to this spectral line.

Thanks!

HannahRobinson3L
Posts: 86
Joined: Wed Sep 30, 2020 9:51 pm
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Re: Sapling #11

Postby HannahRobinson3L » Fri Oct 23, 2020 4:02 pm

Because the line is blue, we know this line belongs to the Balmer series. This means that the electron transitions from higher levels down to the energy level n=2. So we now know that n1=2. We can then use the Rydberg equation to determine the n2 energy level, by converting the given wavelength to frequency and plugging in the Rydberg constant. Hope this makes sense.

Joseph Hsing 2C
Posts: 85
Joined: Wed Sep 30, 2020 9:42 pm

Re: Sapling #11

Postby Joseph Hsing 2C » Sat Oct 24, 2020 3:58 pm

First, make sure you convert the given wavelength to meters so it would be 486.1 x 10^-9 m. Use v=c/lambda to convert to frequency. Plug frequency and n1=2 into Rydberg Equation to find n2. You should get n2=4.


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