The electron in a hydrogen atom is excited to the n=6
shell and emits electromagnetic radiation when returning to lower energy levels. Determine the number of spectral lines that could appear when this electron returns to the lower energy levels, as well as the wavelength range in nanometers.
I got that the number of spectral lines is 5
I also know that the wavelength range is starting from 94 nm.
I need help finishing the statement "The wavelength range is from 94 nm to _____ nm ????
Thanks so much!
Sapling hw "wavelength range"
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Re: Sapling hw "wavelength range"
Hey Kate! Since you know the number of spectral lines is 5, you have to use the equation En= -hr/n^2 where n = 5. You should get an energy of -8.7195x10^-20J. Then you should use the equation Ef-Ei, where Ef = the energy of n=6, and Ei = the energy of n=5. You should get 2.6643 x 10^-20J. Afterwards, you use the equation wavelength = hc/E. Plug 2.6643 x 10^-20J into that equation, and you should get 7460 nm as the answer :) Hope this helps!
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Re: Sapling hw "wavelength range"
Katie Lam 2G wrote:Hey Kate! Since you know the number of spectral lines is 5, you have to use the equation En= -hr/n^2 where n = 5. You should get an energy of -8.7195x10^-20J. Then you should use the equation Ef-Ei, where Ef = the energy of n=6, and Ei = the energy of n=5. You should get 2.6643 x 10^-20J. Afterwards, you use the equation wavelength = hc/E. Plug 2.6643 x 10^-20J into that equation, and you should get 7460 nm as the answer :) Hope this helps!
omg I was making a silly mistake. thank you SO much you're awesome.
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