6 posts • Page 1 of 1
Hannah Alltucker 2H wrote:I think it just wants you to solve for wavelength by making it wavelength=1/r(1/n-1/n2), which would in this case be the inverse.
Thank you for your reply! How would I convert the inverse into regular wavelength in nm?
To isolate lambda, you multiply both sides by lambda so that eventually you'll get lambda = 1/(1.0974*10^7 m/s)((1/nf^2)-(1/ni^2). From there, you should be getting the answer in meters which you can then convert to nanometers.
Who is online
Users browsing this forum: No registered users and 3 guests