Sapling #8 week2-4

H-Atom ()

Moderators: Chem_Mod, Chem_Admin

jia207
Posts: 101
Joined: Wed Sep 30, 2020 9:52 pm

Sapling #8 week2-4

Postby jia207 » Sun Nov 01, 2020 10:30 pm

For this question I keep getting it wrong and the Sapling feedback is tell me to find the wavelength by calculating the inverse first? How do I calculate the inverse of 1/λ?
Attachments
Screen Shot 2020-11-01 at 10.28.21 PM.png

Hannah Alltucker 3L
Posts: 98
Joined: Wed Sep 30, 2020 9:44 pm

Re: Sapling #8 week2-4

Postby Hannah Alltucker 3L » Sun Nov 01, 2020 10:37 pm

I think it just wants you to solve for wavelength by making it wavelength=1/r(1/n-1/n2), which would in this case be the inverse.

Joseph Hsing 2C
Posts: 85
Joined: Wed Sep 30, 2020 9:42 pm

Re: Sapling #8 week2-4

Postby Joseph Hsing 2C » Sun Nov 01, 2020 10:40 pm

I second what Hannah says! Make sure you put an extra pair of parentheses in the denominator when using your calculator.

jia207
Posts: 101
Joined: Wed Sep 30, 2020 9:52 pm

Re: Sapling #8 week2-4

Postby jia207 » Sun Nov 01, 2020 10:40 pm

Hannah Alltucker 2H wrote:I think it just wants you to solve for wavelength by making it wavelength=1/r(1/n-1/n2), which would in this case be the inverse.


Thank you for your reply! How would I convert the inverse into regular wavelength in nm?

Sam Wentzel 1F 14B
Posts: 119
Joined: Wed Sep 30, 2020 9:50 pm
Been upvoted: 1 time

Re: Sapling #8 week2-4

Postby Sam Wentzel 1F 14B » Sun Nov 01, 2020 10:42 pm

Solve for wavelength using algebra

Rachel Kho Disc 2G
Posts: 79
Joined: Wed Sep 30, 2020 9:46 pm

Re: Sapling #8 week2-4

Postby Rachel Kho Disc 2G » Sun Nov 01, 2020 10:49 pm

To isolate lambda, you multiply both sides by lambda so that eventually you'll get lambda = 1/(1.0974*10^7 m/s)((1/nf^2)-(1/ni^2). From there, you should be getting the answer in meters which you can then convert to nanometers.


Return to “Bohr Frequency Condition, H-Atom , Atomic Spectroscopy”

Who is online

Users browsing this forum: No registered users and 1 guest