## Fall 2010 Final Exam

H-Atom ($E_{n}=-\frac{hR}{n^{2}}$)

Antonio Melgoza 2K
Posts: 33
Joined: Fri Sep 25, 2015 3:00 am

### Fall 2010 Final Exam

For question 2A, the final answer is 6. But I don't understand how you get 6 from 1/(n^2) = 2.78 x 10^-2
Can someone explain how you get 6?

Anne Cam 3A
Posts: 71
Joined: Fri Sep 25, 2015 3:00 am

### Re: Fall 2010 Final Exam

It looks like you have the previous steps correct (making ΔE or hv negative because light was emitted, using the right constants, etc.) and all you need to do is solve for n. Multiply both sides by n2, so you will have 1 = (n2)(2.78x10-2). Then divide both sides by 2.78x10-2 to get 1/(2.78x10-2)=n2. Then take the square root of both sides to solve for n. The answer should be about 5.9976 which rounds to 6.