Maximum wavelength in angstroms

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Kailyncanez3G
Posts: 44
Joined: Mon Jan 09, 2023 1:20 am

Maximum wavelength in angstroms

Postby Kailyncanez3G » Mon Dec 04, 2023 11:53 pm

how do you calculate the maximum wavelength in angstroms of the radiation that will eject electrons from the metal using 3.750x 10-19J.

Ahmad Almuti 3K
Posts: 80
Joined: Fri Sep 29, 2023 10:51 am

Re: Maximum wavelength in angstroms

Postby Ahmad Almuti 3K » Tue Dec 05, 2023 12:15 am

Use E=hc/λ and rearrange. λ = hc/E. E is 3.75 x 10^-19 J so simply plug that in. h and c are constants. you will get wavelength. To convert to angstroms, use 1m=1×10^10 Å.
Last edited by Ahmad Almuti 3K on Tue Dec 05, 2023 12:17 am, edited 1 time in total.

Miguel Hernandez LEC 3
Posts: 80
Joined: Thu Oct 12, 2023 8:21 am

Re: Maximum wavelength in angstroms

Postby Miguel Hernandez LEC 3 » Tue Dec 05, 2023 12:15 am

To solve this type of question, you would use the equation E = hv. In this equation E = energy to reject and electron, h is Planck's constant, and v is the frequency. You would also use the equation, c = wavelength/frequency. By rearranging the equation, you should determine wl = hc/energy. You would then plug in the values you've given. (6.626*10^-34)(3*10^8)/3.75*10^-19.


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