Quantum world objective again
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Quantum world objective again
I was also confused on the objective about knowing how to calculate electron transitions for the H-atom spectrum using the En equation. Does this mean the En equation only works for hydrogen atoms? Am I able to use the rydberg equation for hydrogen atoms or do I have to use the En equation?
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Re: Quantum world objective again
Yes the equation
works for determining the energy at a specific n level for hydrogen atoms ONLY.
The Rydberg equation I believe you are talking about is v = - R [ 1/n^2 -1/n^2] - (the first n is the initial energy level and the second is the final, sorry my equation editor was weird) - This equation is only useful in determining the frequency of the emitted or absorbed light or for finding the energy level n that the electron was de-excited to or from. It cannot directly tell you the total energy at a specific level n. This equation is also only for hydrogen atoms.
The Rydberg equation I believe you are talking about is v = - R [ 1/n^2 -1/n^2] - (the first n is the initial energy level and the second is the final, sorry my equation editor was weird) - This equation is only useful in determining the frequency of the emitted or absorbed light or for finding the energy level n that the electron was de-excited to or from. It cannot directly tell you the total energy at a specific level n. This equation is also only for hydrogen atoms.
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- Posts: 67
- Joined: Wed Sep 30, 2020 10:02 pm
Re: Quantum world objective again
With this v = - R [ 1/n^2 -1/n^2] equation couldnt you use it to find the frequency and then convert it into E= frequency times plancs constant to figure out the exact energy?
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Re: Quantum world objective again
Claire_Kim_2F wrote:With this v = - R [ 1/n^2 -1/n^2] equation couldnt you use it to find the frequency and then convert it into E= frequency times plancs constant to figure out the exact energy?
Yes but it’s a two step process. That’s what I meant when I said the equation doesn’t give you the energy directly.
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