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### De Broglie Equation Dividing J*s by kg*m/s

Posted: **Sat Oct 13, 2018 1:59 pm**

by **marcus lin 1E**

So for De Broglie's Equation, you have to divide planck's constant (h) by momentum. But the units of h are in J*s and momentum is in kg*m/s, can someone explain to me how the units cancel out to get a unit appropriate for wavelength?

### Re: De Broglie Equation Dividing J*s by kg*m/s

Posted: **Sat Oct 13, 2018 2:12 pm**

by **Harshita Talkad 4L**

During Friday's lecture, Professor Lavelle said that 1 J= 1 kg.m^2.s^(-2). In the equation, the units are (J.s)/(kg.m/s), so if you plug in the units for J, all the units except for m will cancel out, which gives wavelength in meters.

### Re: De Broglie Equation Dividing J*s by kg*m/s

Posted: **Sat Oct 13, 2018 2:50 pm**

by **shaunajava2e**

1 J= 1 kg.m^2.s^(-2)

the units in the de broglie equation are: (J.s)/(kg.m/s)

this becomes: [(1 kg.m^2.s^(-2))(s)]/(kg.m/s)

the kgs on both sides cancel out

there is a s^(-2) and s on top, and a s on the bottom, these cancel out as well

the m^2 on top cancels out with one m on the bottom to end with a single m which is your resulting units