1.59 6th edition
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Vanessa Reyes_1K
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1.59 6th edition
Problem 1.59 reads: "Each second a certain lamp produces 9.8 x 10^20 photons with a wavelength of 434 nm. How much energy (in joules) is produced as radiation at this wavelength?". Where the does the number of photons fit into an equation?
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Schuyler_Howell_4D
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Re: 1.59 6th edition
Once you use the equation: E=hc(lambda)^-1
you will get energy in joules per photon. You then multiply that by 9.8 x 10^20 which is the number of photons.
(You should get 450 J. )
you will get energy in joules per photon. You then multiply that by 9.8 x 10^20 which is the number of photons.
(You should get 450 J. )
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