1B.5


Moderators: Chem_Mod, Chem_Admin

Megan Vu 1J
Posts: 101
Joined: Thu Jul 25, 2019 12:15 am

1B.5

Postby Megan Vu 1J » Tue Oct 15, 2019 12:46 pm

In this question, it ask. "The gamma-ray photons emitted by the nuclear decay of a techne- tium-99 atom used in radiopharmaceuticals have an energy of 140.511 keV. Calculate the wavelength of these gamma-rays."

For 140.511 keV, how would this be converted back to Joules? Would we be expected to know this by the test?

A Raab 1K
Posts: 56
Joined: Sat Aug 24, 2019 12:16 am

Re: 1B.5

Postby A Raab 1K » Tue Oct 15, 2019 1:13 pm

I just looked up what keV was, so hopefully we don't have to know that for tests (maybe it'll be provided?)
1 keV = 1.60217662e-16 joules

Rachel Yu 1G
Posts: 113
Joined: Fri Aug 09, 2019 12:15 am

Re: 1B.5

Postby Rachel Yu 1G » Tue Oct 15, 2019 2:43 pm

I don't think we would have to memorize the conversion. If we needed it for a test it would either be given or on the formula sheet.

Tiffany Chao 2H
Posts: 117
Joined: Fri Aug 09, 2019 12:17 am

Re: 1B.5

Postby Tiffany Chao 2H » Tue Oct 15, 2019 3:42 pm

The equation sheet should provide the conversion from keV to J is 1 keV = 1.6022 x 10^-16 J.


Return to “DeBroglie Equation”

Who is online

Users browsing this forum: No registered users and 2 guests