1B.7 HW prob

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Doris Cho 1D
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Joined: Thu Jul 11, 2019 12:16 am

1B.7 HW prob

Postby Doris Cho 1D » Sat Oct 19, 2019 3:07 pm

for parts b and c where do you find out that to convert the atoms to joules it's a multiplication of 3.37x10^-19? I can't find that conversion anywhere...

Anne Tsai 1F
Posts: 50
Joined: Thu Jul 25, 2019 12:15 am

Re: 1B.7 HW prob

Postby Anne Tsai 1F » Sat Oct 19, 2019 4:09 pm

You should have gotten 3.37 x 10^-19 J as your answer for part a when calculating the energy of one sodium atom, which you then use to convert to grams and moles in parts b and c.

Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

Re: 1B.7 HW prob

Postby Rodrigo2J » Sun Oct 20, 2019 1:49 pm

For this problem, you have to remember that one sodium atom generates one photon, so the energy you calculate in part a is the same as the energy emitted by one sodium atom when it generates a photon. Knowing this just use the conversion (answer to part a in Joules)/1atom Na to find the answers to part b and c.

Siddiq 1E
Posts: 106
Joined: Fri Aug 09, 2019 12:15 am

Re: 1B.7 HW prob

Postby Siddiq 1E » Sun Oct 20, 2019 1:50 pm

For E=hv, this equation gives the energy of one photon. Every time you use this equation, the energy given is per photon.

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