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n1 is nFinal and n2 is nInitial, which is an easier way of looking at it. Also, for this equation, you have to always make sure the smaller n-value (bigger number overall) is in front, or else it does not work. I have no idea why, but you can always default to the other equation Lavelle gave us if this one doesn't work, lol
For this equation, I like to think of it as v=R(1/nfinal^2 - 1/ninitial^2), meaning the final n-value(the smaller one) comes first in the equation and conversely the initial larger n-value comes second in the equation. Keep in mind that the resulting fraction inside the parenthesis(the number multiplied by R) should be positive. If the fraction is negative then the order of the n-values in the equation is wrong and will lead to an incorrect answer. Hope this helps
I would prefer you think about it as initial energy level and final energy level rather than just mathematically as light operates at discrete energy levels. It is basically n(final)- n(initial) and n2 should be the initial shell where it begins and n1 where it ends up.
Yeah so n1 is final and n2 is initial. A better way to remember it for me is the overall energy is derived from the equation change in E=E(final)-E(intial). Therefore the n1 comes from the final and by the way dont use the ryberg equation makes it harder on yourself.
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