Week 2,3,3 Sampling #25

Moderators: Chem_Mod, Chem_Admin

Posts: 93
Joined: Wed Sep 30, 2020 9:44 pm

Week 2,3,3 Sampling #25

Postby VanessaZhu2L » Thu Oct 29, 2020 1:29 am

For 25, when finding the energy of the photon and electron, the solution gives two different ways to solve it.

For the photon, they use E=hv and c=vλ and for electron, they used λ=h/p and e=1/2mv^2.

I was wondering why they used the two different methods and how you know which equations work with the electrons or the photons.

Thank you!

Stuti Pradhan 2J
Posts: 159
Joined: Wed Sep 30, 2020 9:32 pm
Been upvoted: 5 times

Re: Week 2,3,3 Sampling #25

Postby Stuti Pradhan 2J » Thu Oct 29, 2020 1:33 am

The equations E=hv and c=vλ refer to electromagnetic radiation and therefore can only be used for photons. On the other hand, λ=h/p and ke=1/2mv^2 are for any particles that have rest mass. The second two equations can be used for electrons, neutrons, protons, etc. Since photons have no rest mass, the DeBroglie and kinetic energy equations cannot be used for them.

Hope this helps!

Posts: 78
Joined: Wed Sep 30, 2020 9:51 pm
Been upvoted: 1 time

Re: Week 2,3,3 Sampling #25

Postby AnnaNovoselov1G » Thu Oct 29, 2020 8:57 am

I also wanted to add that you can use c=vλ and E=hv when calculating whether an electron can be ejected because electrons absorb the energy of a photon that strikes them. For instance, an energy of light (hv) that equals the work threshold of a metal could eject the electrons (= the energy the electrons would get). But directly, E=hv and c=vλ can only be used for photons because they are specific to electromagnetic radiation.

Return to “DeBroglie Equation”

Who is online

Users browsing this forum: No registered users and 2 guests