Question #25 asks
The E Coli bacterium is about 2.4 μm long. Suppose you want to study it using photons of that wavelength or electrons having that de Broglie wavelength.
What is the energy E photon of the photon?
How do I solve this?
energy of a photon
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Re: energy of a photon
Hi!
Since the energy of a photon is equal to its frequency multiplied by Planck's constant, we can rewrite the equation (c = wavelength * frequency) to solve for frequency in terms of wavelength. We can then replace frequency in the E = hv equation with the term from the rewritten (c = wavelength * frequency) equation and solve for the energy. I hope this helps!
Since the energy of a photon is equal to its frequency multiplied by Planck's constant, we can rewrite the equation (c = wavelength * frequency) to solve for frequency in terms of wavelength. We can then replace frequency in the E = hv equation with the term from the rewritten (c = wavelength * frequency) equation and solve for the energy. I hope this helps!
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Re: energy of a photon
Hello,
You would use the equations E = HV and c= λv. Convert the 2.4 μm to meters and insert that into c= λv for λ. Isolate for v, then use that to solve the E = HV equation
You would use the equations E = HV and c= λv. Convert the 2.4 μm to meters and insert that into c= λv for λ. Isolate for v, then use that to solve the E = HV equation
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Re: energy of a photon
You would first start off by using the equation c= wavelength*frequency. you convert 2.4 μm to meters using unit analysis into meters and then solve for frequency. Once calculated, you would then plug your frequency value into E=HV, where h is represented by Plank's constant and V is the frequency and get your value for energy.
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