Question #25 asks
The E Coli bacterium is about 2.4 μm long. Suppose you want to study it using photons of that wavelength or electrons having that de Broglie wavelength.
What is the energy E photon of the photon?
How do I solve this?
energy of a photon
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Re: energy of a photon
Hi!
Since the energy of a photon is equal to its frequency multiplied by Planck's constant, we can rewrite the equation (c = wavelength * frequency) to solve for frequency in terms of wavelength. We can then replace frequency in the E = hv equation with the term from the rewritten (c = wavelength * frequency) equation and solve for the energy. I hope this helps!
Since the energy of a photon is equal to its frequency multiplied by Planck's constant, we can rewrite the equation (c = wavelength * frequency) to solve for frequency in terms of wavelength. We can then replace frequency in the E = hv equation with the term from the rewritten (c = wavelength * frequency) equation and solve for the energy. I hope this helps!
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Re: energy of a photon
Hello,
You would use the equations E = HV and c= λv. Convert the 2.4 μm to meters and insert that into c= λv for λ. Isolate for v, then use that to solve the E = HV equation
You would use the equations E = HV and c= λv. Convert the 2.4 μm to meters and insert that into c= λv for λ. Isolate for v, then use that to solve the E = HV equation
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Re: energy of a photon
You would first start off by using the equation c= wavelength*frequency. you convert 2.4 μm to meters using unit analysis into meters and then solve for frequency. Once calculated, you would then plug your frequency value into E=HV, where h is represented by Plank's constant and V is the frequency and get your value for energy.
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Re: energy of a photon
Hi! First, you would use the equation c = (lambda)(v) to solve for frequency by converting the wavelength of 2.4 μm to meters and rearranging the equation to solve for v. Then, you use the equation E = hv to solve for the energy of the photon by multiplying Planck's constant (h) and the frequency (v) value you calculated in the previous step. Hope this helps!
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Re: energy of a photon
Hey,
So you would want to start off by converting the 2.4 micromolar to meters. Next I would change the c= lambda/v equation to isolate the v so v= lambda/c. From these we can solve for v. After solving for v you want to put your value into E=hv and there you go. Hope this helps!
So you would want to start off by converting the 2.4 micromolar to meters. Next I would change the c= lambda/v equation to isolate the v so v= lambda/c. From these we can solve for v. After solving for v you want to put your value into E=hv and there you go. Hope this helps!
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Re: energy of a photon
Knowing the wavelength means using the equations we have, c=lambda(v) and E=hv we could calculate first v to plug into the second equation to then solve for energy, knowing the inverse relationship of wavelength and frequency as well as that Energy is equal to planck's constant times v.
Re: energy of a photon
hi, to find the energy of the photon, you use E = hc/lambda. if you go further in the problem, you used lambda = h/mv to find the velocity, and then use E = 1/2mv^2 to find the energy of the electron.
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