Hi,
I was able to find the work function easily, but how do you find the maximum number of electrons ejected? The first part was "When a metal was exposed to photons at a frequency of 1.47×1015 s−1, electrons were emitted with a maximum kinetic energy of 3.30×10−19 J." My work function came out to 6.44022×10−19
The second part asks, "What is the maximum number of electrons that could be ejected from this metal by a burst of photons (at some other frequency) with a total energy of 3.89×10−7 J?" Please help explain how to solve this!!
Sapling #4
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 55
- Joined: Wed Sep 30, 2020 10:06 pm
Re: Sapling #4
Maddie Turk Disc 2C wrote:Hi,
I was able to find the work function easily, but how do you find the maximum number of electrons ejected? The first part was "When a metal was exposed to photons at a frequency of 1.47×1015 s−1, electrons were emitted with a maximum kinetic energy of 3.30×10−19 J." My work function came out to 6.44022×10−19
The second part asks, "What is the maximum number of electrons that could be ejected from this metal by a burst of photons (at some other frequency) with a total energy of 3.89×10−7 J?" Please help explain how to solve this!!
For the second part, you want to use the equation:
work function x electrons = total energy
for you, it would be 6.44022x10^-19 x electrons = 3.89x10^-7
Then, just solve for electrons, so it would be electrons = (3.89x10^-7)/(6.44022x10^-19)
Hope this helps :)
-
- Posts: 90
- Joined: Wed Sep 30, 2020 9:48 pm
Re: Sapling #4
Nathaly Cruz 2D wrote:Maddie Turk Disc 2C wrote:Hi,
I was able to find the work function easily, but how do you find the maximum number of electrons ejected? The first part was "When a metal was exposed to photons at a frequency of 1.47×1015 s−1, electrons were emitted with a maximum kinetic energy of 3.30×10−19 J." My work function came out to 6.44022×10−19
The second part asks, "What is the maximum number of electrons that could be ejected from this metal by a burst of photons (at some other frequency) with a total energy of 3.89×10−7 J?" Please help explain how to solve this!!
For the second part, you want to use the equation:
work function x electrons = total energy
for you, it would be 6.44022x10^-19 x electrons = 3.89x10^-7
Then, just solve for electrons, so it would be electrons = (3.89x10^-7)/(6.44022x10^-19)
Hope this helps :)
Thank you so much!! This helps a lot! Is (work functions x electrons = total energy) a specific equation? By that I mean does it have a specific name?
Return to “DeBroglie Equation”
Who is online
Users browsing this forum: No registered users and 7 guests