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[Hana Sigsbee 3B]

The E.coli bacterium is about 2.0 μm long. Suppose you want to study it using photons of that wavelength or electrons having that de Broglie wavelength.
how would I start this problem to find the energy of the photon as well as the energy of the electron?

[Geethika Janga 1L]

To find the energy of the photon, you simply have to use E=hc/λ. With λ=2 micrometers, then to find the other value, you have to manipulate the De Broigle equation: λ=h/p where p=(m)(velocity).

[Brandon Pham 1H]

For the energy of the photon, start by converting the given length of the bacterium to meters. Plug that into the equation E=hc/lambda and ta-da.

[Hana Sigsbee 3B]

so on this problem, I got the energy for the photon easily but for some reason, the energy for the electron is giving me trouble. Could someone please walk me through that part a little more thoroughly? I've done it a couple of times now and I'm still not sure what I'm doing wrong.

[claire ikemiya_2I]

So to help you with finding the electron, you need to start by finding the velocity using De Broglie's equation (v = h/(m*lamda). Once you get the velocity, you plug it into E = 1/2(m)(v^2) and you are left with the energy of the electron! Hope that helps.