Achieve HW #15

[Natalie Vu 1I]

You use an electron microscope in which the matter wave associated with the electron beam has a wavelength of 0.0363 nm. What is the kinetic energy of an electron in the beam, expressed in electron volts?

These are my steps:

v = h/m*wavelength
v= 6.62608*10^-34/(9.11*10^-31)(0.0363*10^-9)
v = 20036952.7

Ke = 1/2(m)(v^2)
Ke = 1/2(9.11*10^-31)(20036952.7)^2
Ke = 1.829 * 10^-16

Then finally, 1.829*10^-16/1.602*10^-19

And I get 1.142 * 10^-35 Ev

Can someone point out where I went wrong in the process?

[Joellen 1B]

Where did you get the equation v = h/m*wavelength?

[Joellen 1B]

Also, I think you went wrong on the last part when converting it from J to eV. When I plugged in (1.83x10^-16)/(1.602x10^-19) I got 1.14x10^3

Probably just a calculator error