Nikta's Week 8 workshop (Answer Key Posted)

[Chem_Mod]

Hello everyone,

Unfortunately, tomorrow I have a midterm and I will be moving my session to this Friday, March 1st, from 5 pm to 7 pm over Zoom. I will be posting the Zoom link, the worksheet, and the review sheet when we get closer to Friday.

Thank you so much for understanding!

--Nikta

[Chem_Mod]

Hello everyone!

Here is the Zoom meeting for tomorrow. I will also attach the review sheet and the worksheet that I will go through.

Topic: NIKTA SEYEDIN's Zoom Meeting
Time: Mar 1, 2024 05:00 PM Pacific Time (US and Canada)

Join Zoom Meeting
https://ucla.zoom.us/j/94179357794?pwd= ... NXYWhzdz09

Meeting ID: 941 7935 7794
Passcode: 773356

[Chem_Mod]

Here is the answer key!

[HaleyWong1A]

Hi Nikta! Can you or anyone explain to me how you solved for K in the second part of question 3. I was using the equation E = E* -(.05916/2)log(K) and solving for K while setting E = 0. When I did this I got K = 2.0117 x 10^69. Where am I going wrong?

[Chem_Mod]

Hello! The reason you got a slightly different answer is because 10^69 is a very large number and when you input it in the calculator, it rounds it differently. As long as you say 10^69, it is enough and the slight variation doesn't matter.

[305963519]

In question 3b, why did you use the equation E=Ecell-(0.0542/n) x logQ instead of deltaG=-RTlnK or Ecell=(RT/nF)lnK?

[Chem_Mod]

For this question, I first wrote the general formula E=Ecell-(0.0542/n) x logQ, then since it was at equilibrium and we know E=0, I wrote Ecell=(0.0592/n) x logK and derived the expression for solving K. Hopefully that helps