Quiz Preparation #5  [ENDORSED]

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Quiz Preparation #5

Postby Jose_Arambulo_2I » Fri Oct 07, 2016 1:42 pm

Hi, I'm just a tad confused with the 5th problem on the quiz 1 preparation (pg. 28). In the problem, it states that the bowling ball's speed is "2.35+/-0.1ms^-1." What then would the delta v value be if I'm trying to solve for delta p?

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Re: Quiz Preparation #5  [ENDORSED]

Postby Amy_Shao_2D » Fri Oct 07, 2016 3:36 pm

Delta v would be 2 times .1 which is .2, since .1 is the uncertainty in the velocity and the value of v can range from 2.25 to 2.45. You can also think of delta v as 2.45-2.25, which is .2. Hope this helps!

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