post-module question #22

[Stephanie tran 1J]

Use the above uncertainty in velocity (correct model) to calculate the electron's uncertainty in kinetic energy. Then calculate the uncertainty in kinetic energy per mole of electrons (that is, per mole of hydrogen atoms). Comment on your value.
I don't understand how to calculate the uncertainty in kinetic energy per mole of electrons. How do you convert it to per mole of electrons?

[Jasmine Wu 1L]

Hi! I had a similar question to this.

You would multiply the kinetic energy that you found by Avogadro's constant to get J/mol.

[Justin Lau 1D]

Basically the kinetic energy value is per electron; in fact, all calculations for this chapter are all specifically for one molecule i.e. per electron, per photon, etc. Because the value is for a single electron in this case, the answer is technically J/electron. To get the value for an entire mole of electron, we need to multiply the J/electron value by Avogadro's number (6.022x10^23 electrons/mol) to get the final J/mol answer, as stated above.