Hi!!
I have a question regarding the Uncertainty principle. If given a problem where the momentum uncertainty, for example, is + or - 2, does that mean the uncertainty amount is 4? Or do you have to take into account the value of the momentum?
Thanks!
Uncertainty Principle [ENDORSED]
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Re: Uncertainty Principle
The uncertainty amount is 4. You don't need to take into account the actual momentum value.
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Re: Uncertainty Principle
Also if you use number 1.45 as a practice problem, the solutions manual is incorrect. The actual velocity given is 5.00 5.0m/s
Thus, =10.0m/s NOT 5.0m/s as the solution manual incorrectly states. Therefore, your answer is =6.7x10-37m
Thus, =10.0m/s NOT 5.0m/s as the solution manual incorrectly states. Therefore, your answer is =6.7x10-37m
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Re: Uncertainty Principle [ENDORSED]
An easy way to remember this is to think of delta v as the change in v like in math. So, we arent concerned with the value of v, but rather the difference between the two limits to its domain.
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Re: Uncertainty Principle
The uncertainty is 4. If the problem states +/- 2, that means 2 from 0 both ways, added together, gives you four.
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