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### 1.55 part b

Posted: **Mon Apr 30, 2018 9:14 pm**

by **Husnia Safi - 1K**

In this question it is given that absorption occurs at 3600 cm^-1 and asks: what is the energy, in joules, that corresponds to that absorption?

It shows that the equation used is E = (c)(h)(v).

Im just curious as to where this equation came from?

### Re: 1.55 part b

Posted: **Tue May 01, 2018 12:41 am**

by **Kara Justeson 1B**

I might be wrong but I think the equation used for this problem was just E=hv. In part a you would find the frequency based on the given wavelength, and in part b, you would use the frequency you found in part a and just plug it into the equation E=hv.

### Re: 1.55 part b

Posted: **Tue May 01, 2018 1:30 am**

by **Jaquelinne Rodriguez-Lopez 1L**

the question states they express energy in terms of v/c with units cm^-1. cm^-1 is basically 1/cm, right? so in order to get cm/1, c in v/c must be brought up to the numerator, thus v*c.