Module Question #17


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Alysia Garcia 1B
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Joined: Wed Feb 21, 2018 3:02 am

Module Question #17

Postby Alysia Garcia 1B » Mon May 07, 2018 9:59 pm

For this question, I am just multiplying the speed of light by 1/100 by the mass of the electron (9.109x10^-31 kg) to find the uncertainty in momentum. This gave me 3x10^6 and then divided h/4pi by the number I found but I somehow am not getting any of the given answers. Does anyone know what error I am making?
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Nahelly Alfaro-2C
Posts: 59
Joined: Wed Nov 15, 2017 3:04 am

Re: Module Question #17

Postby Nahelly Alfaro-2C » Mon May 07, 2018 11:18 pm

You are starting the problem correctly by multiplying the speed of light to the mass of an electron to 1/100; however, your uncertainty in momentum is not 3x10^6. The uncertainty in momentum is actually 2.731 x 10^-24 which is the mistake is made. From there like you mentioned, you would divide the uncertainty in momentum by h/4pi which will give the answer to one of the answer choices provided in the question.

abbydouglas1K
Posts: 65
Joined: Fri Sep 28, 2018 12:26 am

Re: Module Question #17

Postby abbydouglas1K » Thu Oct 25, 2018 8:56 pm

Why do the answers have 1 sig fig ?

zoepamonag4C
Posts: 30
Joined: Fri Sep 28, 2018 12:28 am

Re: Module Question #17

Postby zoepamonag4C » Thu Oct 25, 2018 9:14 pm

I think it's because 3.0x10^6 has 1 sig fig.

Gillian Ward 1F
Posts: 61
Joined: Fri Sep 28, 2018 12:27 am

Re: Module Question #17

Postby Gillian Ward 1F » Thu Oct 25, 2018 9:16 pm

I thought of it as 1/100 having one sig fig


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