Delta x

[Ruiting Jia 4D]

If the uncertainty equation is delta p * delta x is greater than or equal to 1/2 h/2pi, then can we combine m*delta x (delta p) with delta x so that it's m*delta x^2?

[caseygilles 1E]

Well, the change in momentum can be replaced with mass times the change in velocity. Momentum is not mass times position (m*x) as you are referring to it. So, the proper way to substitute for uncertainty in momentum would be m*delta v, not m*delta x. Therefore, the total equation would be (m*delta V)(delta X) >= h/4pi