Value of Delta X
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Re: Value of Delta X
When we're given ∆x, it's usually the diameter of an atom, but one of the problems in the book uses diameter of a nanoparticle. I think in general we will be given some sort of diameter.
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Re: Value of Delta X
Sometimes the question with give you a plus/minus value for deltaX (say +/-5) which means you have to double that value (deltaX=10) before plugging it into the equation.
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Re: Value of Delta X
The delta x in the equation is usually in meters and is often what is solved for or given. If it is in pm you would need to convert it to m so you can solve the problem.
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Re: Value of Delta X
I agree with the previous replies, delta x is usually in meters (m). Delta x describes the position, sometimes the problem gives it as a radius which is the same thing as the position.
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Re: Value of Delta X
So if the radius is given that is the electron's uncertainty in position? Or do we have to multiple it by 2 so it can be the diameter?
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Re: Value of Delta X
I think we would have to multiply the radius by 2 to get the diameter. We want delta x to be the full range of where the electron could be.
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Re: Value of Delta X
Delta X is usually the diameter in meters. If it is given in radius you should use that in meters.
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Re: Value of Delta X
In the question 1b28, the diameter is given as 2.00x10^2 nm. Should I use 2.00x10^-7 meters for the diameter for delta X?
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