### Value of Delta X

Posted:

**Mon Oct 22, 2018 12:11 am**For our purposes, will the value of delta X always be the diameter of the atom?

Created by Dr. Laurence Lavelle

https://lavelle.chem.ucla.edu/forum/

https://lavelle.chem.ucla.edu/forum/viewtopic.php?f=19&t=34542

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Posted: **Mon Oct 22, 2018 12:11 am**

For our purposes, will the value of delta X always be the diameter of the atom?

Posted: **Mon Oct 22, 2018 8:56 am**

When we're given ∆x, it's usually the diameter of an atom, but one of the problems in the book uses diameter of a nanoparticle. I think in general we will be given some sort of diameter.

Posted: **Mon Oct 22, 2018 2:20 pm**

Sometimes the question with give you a plus/minus value for deltaX (say +/-5) which means you have to double that value (deltaX=10) before plugging it into the equation.

Posted: **Tue Oct 23, 2018 12:25 pm**

Yesterday at office hours the TA said delta X should be in meters

Posted: **Tue Oct 23, 2018 12:34 pm**

The delta x in the equation is usually in meters and is often what is solved for or given. If it is in pm you would need to convert it to m so you can solve the problem.

Posted: **Wed Oct 24, 2018 9:59 pm**

I agree with the previous replies, delta x is usually in meters (m). Delta x describes the position, sometimes the problem gives it as a radius which is the same thing as the position.

Posted: **Wed Oct 24, 2018 11:48 pm**

So if the radius is given that is the electron's uncertainty in position? Or do we have to multiple it by 2 so it can be the diameter?

Posted: **Thu Oct 25, 2018 1:53 am**

I think we would have to multiply the radius by 2 to get the diameter. We want delta x to be the full range of where the electron could be.

Posted: **Fri Oct 26, 2018 11:35 am**

Delta X is usually the diameter in meters. If it is given in radius you should use that in meters.

Posted: **Wed Dec 04, 2019 9:34 pm**

In the question 1b28, the diameter is given as 2.00x10^2 nm. Should I use 2.00x10^-7 meters for the diameter for delta X?