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### Heisenberg- In relation to wavelength

Posted: Sat Oct 27, 2018 3:05 pm
Question: If the uncertainty in the momentum increases for a given particle what does this mean for the uncertainty in its wavelength?

I was wondering what the relationship between these two uncertainties are and how one can potentially affect the other?

### Re: Heisenberg- In relation to wavelength

Posted: Sat Oct 27, 2018 3:07 pm
Because of λ=h/p, an increase in uncertainty of p increases the uncertainty of λ.

### Re: Heisenberg- In relation to wavelength

Posted: Sat Oct 27, 2018 3:46 pm
I thought it would be the opposite? Because dividing planks constant by a larger number would lead to a smaller wavelength value? Because don't they have an indirect relationship?

### Re: Heisenberg- In relation to wavelength

Posted: Sat Oct 27, 2018 3:50 pm
The uncertainty in momentum is inversely proportional to the uncertainty in wavelength, meaning a larger uncertainty in momentum will lead to a smaller uncertainty in wavelength, and vice versa.

### Re: Heisenberg- In relation to wavelength

Posted: Sat Oct 27, 2018 5:14 pm
Because of the inverse relationship between momentum and wavelength shown in the de Broglie equation(λ=h/p), increasing the uncertainty of momentum will decrease the uncertainty of wavelength.

### Re: Heisenberg- In relation to wavelength

Posted: Sat Oct 27, 2018 5:14 pm
Because of the inverse relationship between momentum and wavelength shown in the de Broglie equation(λ=h/p), increasing the uncertainty of momentum will decrease the uncertainty of wavelength.

### Re: Heisenberg- In relation to wavelength

Posted: Sat Oct 27, 2018 6:15 pm
chrisavalos- 1K wrote:Question: If the uncertainty in the momentum increases for a given particle what does this mean for the uncertainty in its wavelength?

I was wondering what the relationship between these two uncertainties are and how one can potentially affect the other?

Because there's an inverse relationship between momentum and wavelength, an increase in the uncertainty of momentum will entail a decrease in the uncertainty of wavelength.

### Re: Heisenberg- In relation to wavelength

Posted: Mon Oct 29, 2018 11:29 pm
Because of the inverse relationship between momentum (p) and wavelength(lambda) is given in De Broglie's equation, lambda=h/p, therefore, when p is increased, the value of lambda decreases.