## Test 2 1b

$\Delta p \Delta x\geq \frac{h}{4\pi }$

Moryel Yashar 1J
Posts: 31
Joined: Fri Sep 28, 2018 12:15 am

### Test 2 1b

How does the change in uncertainty in momentum affect the uncertainty in its wavelength?

Does this relate to the de Broglie equation?
Last edited by Moryel Yashar 1J on Sat Nov 03, 2018 10:46 pm, edited 1 time in total.

Lasya Gudipudi 1A
Posts: 60
Joined: Fri Sep 28, 2018 12:15 am

### Re: Test 3 Version 2 1b

The change in uncertainty in momentum is inversely proportional to the uncertainty in its wavelength. Yes, you have to use De Broglie because wavelength equals h/momentum, so if momentum decreases, then wavelength increase and vice versa.

Hai-Lin Yeh 1J
Posts: 89
Joined: Fri Sep 28, 2018 12:16 am
Been upvoted: 1 time

### Re: Test 2 1b

If there is uncertainty in momentum, then there is uncertainty in wavelength because wavelength equal h/(uncertainty of momentum [p]) results in uncertainty in wavelength = h/ (uncertainty in momentum). If the uncertainty in momentum increases, the uncertainty in its wavelength decreases. If uncertainty in momentum decreases, uncertainty in wavelength increases.