## 1B. 27

$\Delta p \Delta x\geq \frac{h}{4\pi }$

Abigail Carter 4G
Posts: 50
Joined: Sat Sep 07, 2019 12:19 am

### 1B. 27

A bowling ball of mass 8.00 kg is rolled down a bowling alley lane at 5.00 +/- 5.0 m.s-1. What is the minimum uncertainty in its position?

Justin Sarquiz 2F
Posts: 106
Joined: Fri Aug 30, 2019 12:15 am

### Re: 1B. 27

(delta p) (delta x) > h/(4pi)
delta x > h/(4pi)[(m delta v)]
delta x > h/(4pi)(8 x 10) The change in velocity is 2 times the +/- number. So change in velocity is 2 x 5=10.
delta x > 6.59 x 10^-37 m The solution manual makes an error and says that the change in velocity is 5 when it should be 10, so this is the correct answer.