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Postby KDang_1D » Mon Oct 14, 2019 3:26 pm

What is the significance of momentum in the Heisenberg Indeterminacy equation? Why not write the formula in terms of if you can't interpret anything from unless you convert it to velocity using p=mv?

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Re: Momentum

Postby Khushboo_3D » Mon Oct 14, 2019 6:51 pm

The whole idea behind bringing momentum into the picture is to emphasize the fact that an uncertainty in velocity results in an uncertainty in momentum, since we know the mass of the object and it does not change. Moreover, we need the change in momentum to calculate the uncertainty because, according to Heisenberg's uncertainty indeterminacy equation:
(Indeterminacy in momentum) X (Indeterminacy in position) >= h/ 4 pi

Ziyan Wang 3J
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Re: Momentum

Postby Ziyan Wang 3J » Mon Oct 14, 2019 11:09 pm

Because for some objects (such as photon), they have no mass, but they have momentum. It will be non-sense to write it into delta x * m * delta v>= h/4pi for those objects.

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