## 1D.4

$\Delta p \Delta x\geq \frac{h}{4\pi }$

Parker Smith
Posts: 102
Joined: Thu Jul 25, 2019 12:15 am

### 1D.4

Can someone assist me with this problem? I understand how to find the electron using the 0.83 angstrom measurement, but I don't understand the second portion of the problem "relative to finding it at the nucleus."

"Evaluate the probability of finding an electron in a small region of a hydrogen 1/ orbital at a distance 0.83a from the nucleus relative to finding it in the same small region located at the nucleus."

AnvitaaAnandkumar_1B
Posts: 56
Joined: Fri Aug 02, 2019 12:15 am

### Re: 1D.4

For the second part of the question, what changes is the uncertainty in position, delta x. The range of the nuclear diameter is generally taken as 1.7 x 10^(-15) metres.

Therefore, you substitute that value into the Heisenberg's indeterminacy equation and calculate the uncertainty in momentum

You then compare these uncertainties in momentum.