1B. 25


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Ghadir Seder 1G
Posts: 102
Joined: Sat Sep 14, 2019 12:17 am

1B. 25

Postby Ghadir Seder 1G » Tue Oct 15, 2019 10:05 pm

In the solutions manual for this problem, it states that h=(1.054 457x10^-34)and converts J. s to kg. m^2.s^-1
My question is where does this value come from in the problem? I thought that H was plank's constant which is 6.626x10^-34?
Can anyone explain to me where this value comes from?

Thank you :) !

Gabriella Bates 2L
Posts: 87
Joined: Thu Jul 11, 2019 12:15 am

Re: 1B. 25

Postby Gabriella Bates 2L » Tue Oct 15, 2019 10:16 pm

1.054 457x10^-34 isn't the value for h, but it is actually the value of h bar. H bar is equal to h/(2pi), and is denoted as an h with a line through the top. Although it's used in the uncertainty principle in the book, it's not necessary to know it because it's just a shorthand.


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