h bar formula  [ENDORSED]


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Brandon Valafar
Posts: 62
Joined: Sat Aug 17, 2019 12:16 am

h bar formula

Postby Brandon Valafar » Sun Oct 20, 2019 3:45 pm

In the textbook it says that h bar in the uncertainty equation is equal to h/2pi. However, in our notes it says that the hbar formula is h/4pi. Which are we supposed to use?

eduardomorales5
Posts: 33
Joined: Fri Aug 30, 2019 12:15 am

Re: h bar formula

Postby eduardomorales5 » Sun Oct 20, 2019 3:50 pm

The more correct one to use is the h/4pi.

Sydney Jacobs 1C
Posts: 59
Joined: Thu Jul 25, 2019 12:15 am
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Re: h bar formula  [ENDORSED]

Postby Sydney Jacobs 1C » Sun Oct 20, 2019 3:56 pm

The formula given during lecture for Heisenberg's Indeterminacy Equation utilized h rather than h bar. It read (delta p)(delta x) is greater than or equal to (h/ 4pi). In the textbook, instead of using (h/4pi), they described the equation in terms of (h bar/2) which is actually equivalent since h bar is equal to (h/2 pi). Therefore, (h/4 pi) and (h bar/2) are both correct.

Milisuryani Santoso 1L
Posts: 44
Joined: Thu Jul 11, 2019 12:15 am

Re: h bar formula

Postby Milisuryani Santoso 1L » Sun Oct 20, 2019 6:26 pm

I don't think it matters which one you use, as long as you know that the original equation is h/4pi. The h bar symbol is just used as a shorthand really for h bar = h/2pi, so it's up to you.

kevinolvera1j
Posts: 67
Joined: Fri Aug 02, 2019 12:15 am

Re: h bar formula

Postby kevinolvera1j » Sun Oct 20, 2019 7:46 pm

Since h bar is equal to (h/2π) it's very useful as shorthand where this value is used often like in Heisenberg indeterminacy equation and the Schrodinger equation. In the Heisenberg equation, the (h-bar/2) is equal to (h/4π) in case you come across the equation using h-bar.


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