HW question


Moderators: Chem_Mod, Chem_Admin

Isabel Day 1D
Posts: 48
Joined: Fri Aug 09, 2019 12:15 am

HW question

Postby Isabel Day 1D » Thu Oct 24, 2019 1:38 pm

1B.27 states: A bowling ball of mass 8 kg is rolled down a bowling alley lane at 5.00+/-5.00 m.s^-1. What is the minimum uncertainty in its position.

I understand how to solve this problem using Heisenberg's uncertainty equation, but I don't understand why delta V is 5.00 m.s^-1. Shouldn't it be 10 m.s^-1 since 5.00 m.s^-1 x 2 = 10 m.s^-1?

AArmellini_1I
Posts: 107
Joined: Fri Aug 09, 2019 12:15 am

Re: HW question

Postby AArmellini_1I » Thu Oct 24, 2019 1:45 pm

You're correct! It's actually an error in the textbook. Lavelle has the explanation under the tab "Solution Manual Errors 7th Edition". With that being said, because Δv = 10.0 m.s-1 then answer is actually Δx = 6.7 x 10-37 m

Camille 4I
Posts: 57
Joined: Sat Aug 24, 2019 12:18 am

Re: HW question

Postby Camille 4I » Mon Oct 28, 2019 12:50 am

How do you know to multiply 5.00 m/s by 2?

Rishika Yadav 3D
Posts: 53
Joined: Wed Sep 11, 2019 12:17 am

Re: HW question

Postby Rishika Yadav 3D » Mon Oct 28, 2019 1:39 am

You multiply 5.00 m/s by 2 because the error is 5.00+/-5.00 m/s, so it is in either direction. This the error is the absolute value (5) times 2.


Return to “Heisenberg Indeterminacy (Uncertainty) Equation”

Who is online

Users browsing this forum: No registered users and 1 guest